Question

I WOULD LIKE TO THANK YOU FOR SOLVING THE EQUATION ​

Answer 1

y²-(y+1)(y+2)/(5y+1)=6

y²-y²-3y-2/(5y+1)=6

-3y -2 = 30y+6

33y+8 = 0

y= -8/33

Answer 2

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$<marquee behaviour-move><fontcolor="red"><h1>ANSWER...</h1></marquee>$

$\frac{ {y}^{2} - (y + 1)(y + 2)}{5y + 1} = 6$

$\frac{ {y}^{2} - ( {y}^{2} +(1 + 2)y + (1)(2)) }{5y + 1} = 6$

$\frac{ {y}^{2} - {y}^{2} - 3y - 2 }{5y + 1} = 6$

$\frac{ - 3y - 2}{5y + 1} = 6$

$6(5y + 1) = - 3y - 2$

$30y + 6 = - 3y - 2$

$33y = - 8$

$y = \frac{ - 8}{33}$

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