Question

identify the substance oxidized and reduced in the following reaction:2H2S(g)+SO2(g)-3S(s)+2H2O(l)

Answer 1

Hey mate..
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First of all we need to know !!

What is oxidation and reduction ?

Oxidation••••>

▪It means a substance gains oxygen during a chemical reaction.

Reduction•••>

▪It means a substance loses oxygen during a chemical reaction.


☆ The given chemical chemical equation is:-

2H2S(g)+SO2(g)------> 3S(s)+2H2O(l)

Here,

>>H2S ( Hydrogen Sulphide ) is getting oxidised to Water ( H20 )

••Reason:-

▪Hydrogen is getting Oxidised it means it is getting oxygen ( 02 )

>> SO2 ( Sulphur Dioxide ) is getting reduced to Sulphur

••Reason:-

▪SO2 is losing oxygen here..i.e. it is getting reduced.

Hope it helps !!

Answer 2

in this equation H2S is getting oxidized