If tanA+sinA=m,tanA-sinA=n then prove that m sq -n sq=4√mn.
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Answered by
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m sq-n sq= (tanA+sinA)sq-(tanA-sinA) sq
=tanA sq+sinA sq+2tanAsinA-tanAsq
-sinA sq+2tanAsinA
=4tanAsinA
=4rot mn
=tanA sq+sinA sq+2tanAsinA-tanAsq
-sinA sq+2tanAsinA
=4tanAsinA
=4rot mn
syedmuheed1982:
Thanks alot
Answered by
2
[in last :- it's 4tanAsinA]
hence,LHS=RHS
proved.
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