Question

If (1, 2) and (3, 4) are the opposite vertices of a parallelogram, then the point of intersection of the diagonals of it is​

Answer 1

Step-by-step explanation:

$\because$ Diagonals of a parallelogram are bisector of each other

$\therefore$ the point of intersection of the diagonals of a parallelogram will be the point of bisection that is mid point of both diagonals.

Hence, by mid-point formula :

$(x, y) = \{ \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\} \\ = \{ \frac{1+3}{2}, \frac{2+4}{2}\} \\ = \{ \frac{4}{2}, \frac{6}{2}\} \\ (x, y)= \{2, 3\}$

Thus, the point of intersection of the diagonals of is (2, 3).