Question

if 10th term of an ap is 19 and sum of first 15 terms is 225 then fifth term of ap is

Answer 1

a10=19
a+9d=19
this is equation 1
now,sum of 15 terms =225
n/2{2a+(n-1)d}=225
15/2(2a+14d)=225
a+7d=15
this is equation 2
now solve both the equations by eliminating method or any other method ,you will get
a=1 and d=2
now fifth term of ap =a +4d
=1+4×2
=1+8
=9
fifth term of ap =9