Question

if 2k+1,6,3k+1 are in AP, then find the value of k​

Answer 1

Answer:

hope it helps u

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Step-by-step explanation:

given:- 2k + 1 , 6 , 3k + 1 are in a.p

so, we know common difference = second term - first term = third term - second term

so, 6 - (2k + 1) = (3k + 1) - 6

=> 6 - 2k - 1 = 3k + 1 - 6

=> 5 - 2k = 3k - 5

=> 5 + 5 = 3k + 2k

=> 10 = 5k

=> k = 2

Answer 2

Answer:

2

Step-by-step explanation:

Since the terms are in AP

6 - 2k-1 = 3k+1 - 6

5k = 10

k = 2

Terms are

5 , 6 , 7