If √3 sinθ - cosθ = 0 , find the value of θ . Please help.
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Given √3 sinθ - cosθ = 0
⇒ √3 sinθ = cosθ
⇒ (sinθ/cosθ) = (1/√3)
⇒ tanθ = (1/√3)
∴ θ = 30°
⇒ √3 sinθ = cosθ
⇒ (sinθ/cosθ) = (1/√3)
⇒ tanθ = (1/√3)
∴ θ = 30°
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general solution of θ belongs to "nπ+π/6" where n is integer
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