Question

If 3 theta is an acute angle,solve the following equation ( cosec 3 theta - 2) ( cot 2 theta - 1 ) = 0

please solve this problem . the answer will be 10 degree , 22(1/2) degree. please solve it​

Answer 1

Answer:

Step-by-step explanation:

We have,

$(cosec3\alpha -2)(cot2\alpha -1)=0$

Either,

cosec 3∝-2 = 0                                 or                                  cot2∝-1 = 0

cosec 3∝ = 2                                                                          cot 2∝ = 1

cosec 3∝ = cosec π/6                                                           cot 2∝ = cot π/4

∝ = π/18                                                                                       ∝ = π/8

Hence ∝ = 10° or 22.5°

Answer 2

here is your answer

hope this helps!!

have a great day!!