if 3x+2x=12 and xy=6 find the value of 9x^2+4y^2
Answers
Answered by
0
since xy=6
so x=6/y
a/q
3x+2x=12
or 3×6/y+2×6/y=12
or 18/y+12/y=12
so 30=12y
5/2=y
x=6/y=6/(5/2)=6×2/5=12/5
9x^2+4y^2
9×12/5×12/5+4×5/2×5/2=1296/25+25=1921/25=76.84
so x=6/y
a/q
3x+2x=12
or 3×6/y+2×6/y=12
or 18/y+12/y=12
so 30=12y
5/2=y
x=6/y=6/(5/2)=6×2/5=12/5
9x^2+4y^2
9×12/5×12/5+4×5/2×5/2=1296/25+25=1921/25=76.84
Similar questions