if (3x-4y)³=27x³-64y³+ax²y+bxy² then find the value if a+b
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i think 3x+4y is the answer
nanditapanchalp2zsjl:
how
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(3x-4y)^3=27x^3-72x^2y+96xy^2+64y^3
if we equivalent both side form your question
we get a=72and b=96 so a+b =168
if we equivalent both side form your question
we get a=72and b=96 so a+b =168
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