If 5.0 grams of aluminium react with 4.45 grams of o2 empirical formula of aluminium oxide
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Answer:
Determine mole ratio of O to Al
moles Al= 5/27=.185
moles Oxygen= 4.45/16=.278
ratio= .278/.185=1.5 (1.5 Oxygen to 1 Aluminum)
therefore formula= Al2O3
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