if √ 5/3 and -√ 5/3 are two zeroes of polynomial 3x^4 +6x^3-2x^2-10x-5, then it's other two zeroes are
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option (a). -1,-1 are the other zeroes of the given polynomial. you can confirm it by substituting the options in the given polynomial
Hope this helps you :)
Hope this helps you :)
siddhartharao77:
I think it will be option (a) : -1,-1
oh yeah sorry i didn't check it thoroughly..one sec lemme change the answer
:-))
thanks for letting me know :)
Its okk Anirudh
I know its option A but the method of finding tats what i want to know
Haha :)
the only way to find it is either breaking it into parts or substituting the answers
Yes
substituting is the fastest way of finding the answer. however, you can also go through the other method too
Answered by
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Given x = root 5/3 and x = root -5/3.
x - root 5/3 = 0 and x + root 5/3 = 0
x^2 - 5/3 = 0.
Given polynomial 3x^4 + 6x^3 - 2x^2 - 10x - 5.
We should apply the division algorithm.
x^2 - 5/3) 3x^4 + 6x^3 - 2x^2 -10x - 5(3x^2 + 6x + 3
3x^4 - 5x^2
-----------------------------------------
6x^3 + 3x^2 - 10x - 5
6x^3 - 10x
---------------------------------------------
3x^2 -5
3x^2 -5
-----------------------------------------------------
0
------------------------------------------------------
Quotient is 3x^2 + 6x + 3
3x(x+1) + 3(x+1)
(3x+1)(x+1) = 0
3(x+1)(x+1) = 0
(x+1)(x+1) = 0
x = -1,-1.
x - root 5/3 = 0 and x + root 5/3 = 0
x^2 - 5/3 = 0.
Given polynomial 3x^4 + 6x^3 - 2x^2 - 10x - 5.
We should apply the division algorithm.
x^2 - 5/3) 3x^4 + 6x^3 - 2x^2 -10x - 5(3x^2 + 6x + 3
3x^4 - 5x^2
-----------------------------------------
6x^3 + 3x^2 - 10x - 5
6x^3 - 10x
---------------------------------------------
3x^2 -5
3x^2 -5
-----------------------------------------------------
0
------------------------------------------------------
Quotient is 3x^2 + 6x + 3
3x(x+1) + 3(x+1)
(3x+1)(x+1) = 0
3(x+1)(x+1) = 0
(x+1)(x+1) = 0
x = -1,-1.
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