If 7128 = 2^p * 3^q * 11^r find the value of p+q+r
Answers
Answered by
2
Answer:
By Prime Factorisation,
7128 = 2×2×2×3×3×3×3×11 = 2³×3⁴×11¹
=> p = 3, q = 4, r = 1
p+q+r = 3+4+1 = 8
Similar questions