Question

if a^2+b^2=13 and ab=6 then find a^2-b^2

Answer 1

answer=66 hope it will help you

Answer 2

HEY FRIEND, HERE IS your @|\|$\/\/€R
${a}^{2} + {b}^{2} = 13 \\ ab = 6 \\ = > {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2 ab \\ = 13 + 2(6) \\ = 25 \\ = > (a + b) = \sqrt{25} \\ a + b = 5 \\ similarly \\ {(a - b)}^{2} = 13 - 2(6) = 1 \\ = > a - b = \sqrt{1} = 1 \\as \: {a}^{2} - {b}^{2} = (a + b)(a - b) \\ substituting \: the \: values \: we \: get \\ {a}^{2} - {b}^{2} = (5)(1) = 5$
So Final Answer = 5

I HOPE IT HELPS...!!!