Math, asked by Moinkhan436, 1 year ago

If a and b are the zeroes of polynomial x^2-5x+6 find vslue of a+b-3ab

Answers

Answered by sartho
3

Answer:

13

Step-by-step explanation:

x^-5x+6=0

x^+3x+2x+6=0

x(x+3) +2(x+3) =0

(x+3)(x+2)=0

x+3=0 √ x+2=0

x=-3 √ x=-2

a=-3 , b=-2

Value of a+b-3ab

= -3+(-2) +3×-3×-2

= -3-2+18

= -5+18

= 13

Similar questions