If ab+bc+ca= 12 and a2 +b2+c2=25 find the value of a3 + b3+c3-3abc
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Step-by-step explanation:
w/k, (a+b+c)²=a²+b²+c²+2(ab+bc+ca)
=25+2(12)
=49
a+b+c=7
so, a³+b³+c³-3abc=(a+b+c). (a²+b²+c²-ab-bc-ca)
=7[25-(12)]
=91
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