Question

if a body moving with an initial velocity of 2ms/s has a displacement of 48m in 6s then the final velocity attained by the body is
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Answer 1

u= 2m/s

s=48m

t= 6s

as=ut+1/2at2

48=2*6+1/2*a*6*6

=6m/s2

v=u+at

=2+6*6=2+36=38m/s

Answer 2

EAnswer:

14m/s

Explanation:

u=2m/s

S=48m

t=6s

v=?

S=ut+1/2 at²

48 = 2 x 6 + 1/2 a x 36

=> 2m/s²

v² = u²+2as

4+2 x 2 x 48

=> 196

v=√196

14