If a3+a8+a10+a16+a18+a23=126. Find S25
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Step-by-step explanation:
a+2d+a+7d+a+9d+a+15d+a+17d+a+22d=126
6a+72d=126
6(a+12d)=126
a+12d=21
a=21-12d ----- 1
a25=a+24d
a25=21-12d+24d (from eqn 1)
a25=21+12d
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