Math, asked by Monieeshan, 1 year ago

If a3+a8+a10+a16+a18+a23=126. Find S25​


Monieeshan: Anyone pls answer it

Answers

Answered by bmugilan123401
5

Answer:

Step-by-step explanation:

a+2d+a+7d+a+9d+a+15d+a+17d+a+22d=126

6a+72d=126

6(a+12d)=126

a+12d=21

a=21-12d ----- 1

a25=a+24d

a25=21-12d+24d (from eqn 1)

a25=21+12d


Monieeshan: wrong answer not a25 we want to find S25
bmugilan123401: We know that
bmugilan123401: Sn=n/2{2a(n-1)d}
bmugilan123401: S25=25/2[2(21-12d)+(25-1)d]
bmugilan123401: =25/2[42-24d+24d]
bmugilan123401: 25/2[42] as -24d and +24d gets eliminated
bmugilan123401: =25×21
bmugilan123401: =525
bmugilan123401: So S25 is 525
Monieeshan: Its correct
Answered by sniperdude98012
1

Answer:

The answer is given above

.... if you find this answer correct pls mark me the brainliest .

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