If abcd is a cyclic quadrilateral then tan(a+c) is
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Solution :
Given ABCD is a cyclic quadrilateral.
A + C = 180°
[ Pair opposite angles are supplementary
in a cyclic quadrilateral ]
Now ,
tan( A + C )
= tan 180°
= tan ( 90 + 90 )
= - cot 90°
= 0
••••
Given ABCD is a cyclic quadrilateral.
A + C = 180°
[ Pair opposite angles are supplementary
in a cyclic quadrilateral ]
Now ,
tan( A + C )
= tan 180°
= tan ( 90 + 90 )
= - cot 90°
= 0
••••
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