If cosA- sinA=√2sinA,prove that cosA +sinA=√2sinA.
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Answer:
cosA+sinA=2–√cosA
(2–√–1)cosA=sinA
cosA1=sinA2–√–1=cos2A+sin2A−−−−−−−−−−−−√1+(2–√–1)2−−−−−−−−−−√=14–22–√−−−−−−√=cosA−sinA1−(2–√–1)
So cosA−sinA=2−2–√4–22–√−−−−−−√=√2-√2÷2
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