Question

if cosec theta-sin theta=m^3 and sec theta-cos theta= n^3. Then eliminate theta.

Answer 1

$cosec \alpha - \sin( \alpha ) = m {}^{3}$
$1 - \sin {}^{2} \alpha = m {}^{3} - - - - - - (1)$
$also \: 1 - \cos {}^{2} \alpha = n {}^{3} - - - - (2)$
Eq(1)+eq(2)
$2 - ( \sin {}^{2} \alpha + \cos {}^{2} \alpha) = m {}^{3 } + n {}^{3}$
m³+n³=1

Answer 2

Hi ..dear...
here is your solution...
hope this helped you..