If f(x)=4[x-1] and g(x)=x+1, how do you find f(g(-1))?
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Answered by
1
Answer:
Step-by-step explanation:
First find g(-1) which is obtained by putting X as -1 in g(x)= -1+1 = 0
g(-1) = 0
Now f(g(-1)) = f(0) = 4[-1] = 4(0) = 0
Answered by
2
★★Heya★★
[ -x ] = - [ x ] when x € Z
[ -x ] = - [ x ] - 1 when x €/ Z
where Z is set of integers.
=>
g(-1) = -1 + 1
g(-1) = 0
So,
F(g(-1)) = 4[ g(-1) - 1 ]
=>
F(g(-1)) = 4 [ 0 - 1 ]
=>
F(g(-1)) = 4 [ -1 ]
=>
F(g(-1)) = 4 × -1
=>
F(g(-1)) = -4
☺️☺️
[ -x ] = - [ x ] when x € Z
[ -x ] = - [ x ] - 1 when x €/ Z
where Z is set of integers.
=>
g(-1) = -1 + 1
g(-1) = 0
So,
F(g(-1)) = 4[ g(-1) - 1 ]
=>
F(g(-1)) = 4 [ 0 - 1 ]
=>
F(g(-1)) = 4 [ -1 ]
=>
F(g(-1)) = 4 × -1
=>
F(g(-1)) = -4
☺️☺️
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