Question

if f(x)=x^2-5x+7 evaluate f(2)-f(-1)+f(1/3) pls fast

Answer 1

given fun. is

f(x)=x^2-5x+7

first we put...

x=2,

f(2)=(2)^2-5×2+7

=4-10+7

=11-10

1

again.

x=-1,put..

f(-1)=-1^2-5×-1+7

=1+5+7

13

again put

x=1/3

f(1/3)=1/3^2-5×1/3+7

=1/9-5/3+7

=(1-15+63)/9

=49/9

then

put all value in ..

f(2)-f(-1)+f(1/3)=1-13+49/9

=-59/9

I hope this is helpful for you.

thank you.

Answer 2

f(x)=x²-5x+7

f(2)=2²-5.2+7=1

f(-1)=-1²-(5.-1)+7=13

f(1/3)=1/3²-5.1/3+7=1/9-5/3+7=

=(1-15+63)/9=49/9=

f2-f(-1)+f(1/3)=1-13+49/9=-12+49/9=(-108+49)/9

=-59/9