Question

if first term of an AP is 3 and common difference is 2 then find its 10th term​

Answer 1

$\tt \underline{Answer: 21}$

Step by step explanation:

First term of an A.P is 3

Common difference is 2.

» a = 3, d = 2

We've to find a10.

Using the formula,

an = a + (n - 1) d

a10 = 3 + ( 10 - 1 ) × 2

a10 = 3 + 18

a10 = 21

Hence, The 10th term of A.P is 21.

Answer 2

Step-by-step explanation:

Let the first term be a and common difference be d.

Given no:-

a = 3 and d = 2

Need to find the value of 10th term

A/Q

$an = a + (n - 1)d \\ \\ a10 = 3 + (10 - 1)2 \\ \\ \: \: \: \: \: \: \: \: = 3 + 18 \\ \\ \: \: \: \: \: \: \: \: = 21$

Hence ,

the 10th term is 21.

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