Question

If n is a natural number, then 12n will always end with an even digit except
(1) 4
(2) 6
(3) 8
(4) 0

Answer 1

HOLA

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4 × 3 = 12

6 × 2 = 12

8 × 1 = 8 , 8 × 2 = 16

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Option 3

8 will never end with digit 12

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0 is not accepted as a even number

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HOPE U UNDERSTAND ❤❤❤

Answer 2

Given:

A mathematical number 12^n, where n is a natural number.

To Find:

The units digit of the value$12^n$ always ends with an even digit except?

Solution:

1. The given expression is$12^n$.

• For n=1, the value$12^n$ has the units digit value 2.
• For n=2, the value$12^n$ has the units digit value 4.
• For n=3 the value$12^n$ has the units digit value 8.
• For n=4 the value$12^n$ has the units digit value 6.
• For n=5 the value$12^n$ has the units digit value of 2 which is the same for n=1.

• For n=6 the value$12^n$ has the units digit value of 4 which is the same for n=2.

• For n=7 the value$12^n$ has the units digit value of 8 which is the same for n=3.

• For n=8 the value$12^n$ has the units digit value of 6 which is the same for n=4.

2. For values 4n+1 ( n can be greater than equal to 0) the value$12^n$ always ends with 2.

3. For values 4n+2 ( n can be greater than equal to 0) the value$12^n$ always ends with 4.

4. For values 4n+3 ( n can be greater than equal to 0) the value$12^n$ always ends with 8.

5. For values 4n ( n can be greater than equal to 0) the value$12^n$ always ends with 6.

6. Therefore, the values never end with 0.

Therefore, 0 is not possible as the units digit of the expression 12^n. Option 4 is the correct answer.