if O is the centre of the circle find angle ACB
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Angle ACB = 1/2 of angle AOB
[ANGLE AT THE CENTRE = 2(ANGLE SUSTENDED AT THE SURFACE )]
angle ACB = 1/2 (80)=40
Answered by
4
Answer:
∠ACB = 40
Step-by-step explanation:
∠AOB = 80
BY degree measure theorem,
∠AOB = 2 ∠ACB
80 = 2 ∠ACB
∠ACB = 40
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