Question

if p(x)=4x^2+3x+(7/2) then find the value of (-3/2)
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Answer 1

Step-by-step explanation:

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Answer 2

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Step by step solution:

$Given \ p(x)=4x^2+3x+\frac{7}{2}\\\\we \ have \ to \ find \ p(-\frac{3}{2})\\\\ putting \ x=-\frac{3}{2}\\\\p(x)=4x^2+3x+\frac{7}{2}\\\\multiply \ by \ 2 \ we \ get\\\\p(x)=8x^{2}+6x+7\\\\p(-\frac{3}{2})=8(-\frac{3}{2})^2+6(-\frac{3}{2})+7\\\\p(-\frac{3}{2})=2\times9-9+7\\\\p(-\frac{3}{2})=9+7\\\\p(-\frac{3}{2})=16$

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