If ∆ PQR ~ ∆XYZ, QR = 3 cm, YZ = 4 cm, ar ∆PQR = 54 cm².then ar ∆XYZ
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Area of ∆XYZ = 96 cm² If ∆ PQR ~ ∆XYZ, QR = 3 cm, YZ = 4 cm, ar ∆PQR = 54 cm²
Step-by-step explanation:
∆ PQR ~ ∆XYZ
QR = 3 cm, YZ = 4 cm
=> QR/YZ = 3/4
Ratio of sides of traingle = (3/4)
Ratio of Area of Similar Triangles = (Ratio of Sides of Similar triangle)²
=> Area of ∆ PQR / Area of ∆XYZ = ( Side of ∆ PQR /Side of ∆XYZ )²
=> 54 / Area of ∆XYZ = ( 3 /4 )²
=> Area of ∆XYZ = 54 * (4/3)²
=> Area of ∆XYZ = 54 * (16/9)
=>Area of ∆XYZ = 6 * 16
=> Area of ∆XYZ = 96 cm²
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