Question

if sin (36+tita)degree =cos (16+tita)degree,then find tita, where (36+tita)degree and (16+tita)degree are both acute angle

Answer 1

Dear, there seems to be a mistake in your question.

It is not tita but theta (θ).

Solution:-

sin(36+θ) = cos (16 + θ) is the question.

We know cos A = sin (90-A)

So we can write,

sin (36+θ) = sin{90-(16+θ)}

=> sin(36+θ) = sin(74-θ)

{Deducting sin from both sides, we get}

=> 36 + θ = 74 - θ

=> θ + θ = 74 -36 = 38

=> 2θ = 38

=> θ = 19° (Ans)

Hope it helps (^_^)

Answer 2

Step-by-step explanation:

hope this helps you

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