if sinA=3/5 find the value of (tan A+SecA ) 2
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tan A = 5/4, sec A= 3/4
tanA+ sec A= 5/4+ 3/4 = 8/4= 2
tanA+ sec A= 5/4+ 3/4 = 8/4= 2
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sin a= 3/5
cos a= 4/5
tan a + sec a
= sin a/cos a + 1 / cos a
= 3/4 + 5/4
= 8/4
= 2
cos a= 4/5
tan a + sec a
= sin a/cos a + 1 / cos a
= 3/4 + 5/4
= 8/4
= 2
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