Math, asked by RRvelar, 1 year ago

if sinA=3/5 find the value of (tan A+SecA ) 2

Answers

Answered by moha2
3
tan A = 5/4, sec A= 3/4
tanA+ sec A= 5/4+ 3/4 = 8/4= 2

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Answered by artyaastha
4
sin a= 3/5
cos a= 4/5

tan a + sec a
= sin a/cos a + 1 / cos a
= 3/4 + 5/4
= 8/4
= 2
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