Physics, asked by GAURAVSEMWAL9472, 1 year ago

If the angle of incidence of a ray is equal to the critical angle at the core – cladding interface of an optical fiber, then in which direction does the ray travel? Explain with neat sketch.

Answers

Answered by thush67
0
which class question
Answered by soniatiwari214
0

Answer:

The ray travels at 90°. There is total internal reflection.

Explanation:

  • The angle of incidence at which the angle of refraction is 90 degrees is known as the critical angle.
  • From an optically more dense media to an optically less dense medium, the light must move.
  • The angle of refraction equals 90° when the angle of incidence is equal to the critical angle.
  • The refracted beam will not emerge from the medium if the angle of incidence is greater than this critical angle instead it will be reflected back into the medium. Total internal reflection is what we refer to as.
  • The following two factors must be present for total internal reflection to occur: the angle of incidence must be greater than the critical angle, and the light must be moving from a medium with a higher refractive index to one with a lower refractive index.

The ray travels perpendicular to its original direction.

#SPJ3

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