Question

If the anions (A) form hexagonal closest packing and cations (C) occupy only 2/3 octahedral voids in it, then what is the general formula of the compound ?
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Answer 1

Number of A atoms per unit cell in hcp lattice=6. Number of octahedral voids=6 Number of octahedral voids occupied by C=(2/3)*6=4 Therefore formula of compound=C4A6=C2A3 Hope it helped. Best of luck:)

Answer 2

Answer:

The general formula of the compound $C_2A_3$.

Explanation:

Number of spheres in HCP = n

Number octahedral voids in HCP lattice = n

Number of anion A = n

Number of octahedral void occupied by the cation C :

=$\frac{2}{3}$ of octahedral void

$=\frac{2}{3}n$

The general formula of the compound :

= $C_{\frac{2}{3}n}A{n}=C_2A_3$

The general formula of the compound $C_2A_3$.