Question

If the displacement of a particle varies with time as rootx= t+7,then

Answer 1

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Answer 2

Answer:

the particle moves with constant acceleration.

Explanation:

√x=t+7

we taken to square both side. then we can write-

x = (t+7)∧2

x = t∧2 + 14t + 49

after doing differentiation

x = 2t+ 14 equat∧n 1 then

2t + 14= 0

2t = 14

t =  14/2

t = 7

put  the value of t in equation 1 then  

x = 2t + 14

x = 2*7 + 14

x = 14 + 14

x = 28

v = dx/dt

v = 28/7

v = 4

if the velocity of particle is variable then acceleration is constant,