if the first three terms of an AP are 3y-1, 3y+5 and 5y+1 respectively,then find y!
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Answered by
3
the value of y=5
hope this helps u
hope this helps u
kannan27:
how?
Answered by
26
a1 = 3y-1
a2 = 3y+5
a3 = 5y+1
d = a2 - a1
= 3y+5 - (3y-1)
= 3y+5 - 3y+1
= 6
d = a3 - a2
6 = 5y+1 - (3y+5)
6 = 5y+1 - 3y-5
10 = 2y
y = 5
Hope this helps
If it helped mark as brainliest
a2 = 3y+5
a3 = 5y+1
d = a2 - a1
= 3y+5 - (3y-1)
= 3y+5 - 3y+1
= 6
d = a3 - a2
6 = 5y+1 - (3y+5)
6 = 5y+1 - 3y-5
10 = 2y
y = 5
Hope this helps
If it helped mark as brainliest
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