if the length of a median of an equilateral triangle is 8 cm then find its area
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Suppose,one side of triangle is y.
so, the base is also y . You all know median is bisect a line .
so one part of this side is y/2.
By pythogorus theorem,
Hypotonus^2 = Height^2 + Base^2
y^2 = 8^2 + (y/2)^2
8^2 = y^2 - y^2™/4
8^2 = 3y^2/4
y^2 = 4* 8^2 /3
y = 2*8/root3
So, one side is 16/root3
Area of equilateral triangle is = root3/4
Area = root3/4*16/root3*16/root3
= 64/root3 Ans
so, the base is also y . You all know median is bisect a line .
so one part of this side is y/2.
By pythogorus theorem,
Hypotonus^2 = Height^2 + Base^2
y^2 = 8^2 + (y/2)^2
8^2 = y^2 - y^2™/4
8^2 = 3y^2/4
y^2 = 4* 8^2 /3
y = 2*8/root3
So, one side is 16/root3
Area of equilateral triangle is = root3/4
Area = root3/4*16/root3*16/root3
= 64/root3 Ans
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