Question

if the letters word DAUGHTER are to be arranged so that vowels occupy the odd places then number of different words are???

Answer 1

hope my answer helps you
pls follow me for more answers

Answer 2

Answer: There are 2880 different words.

Step-by-step explanation:

Since we have given that

DAUGHTER

Here, A, U, E are vowels.

And there are 5 consonants.

So, there are 4 odd places.

so, we can choose 3 out of 4 odd places to put the vowel

is given by

$^4C_3=4$

For each of those we can rearrange the 3 vowels is given by

$^3P_3=6$

And we can rearrange the 5 consonants is given by

$^5P_5=120$

so, total number of different words are

$4\times 6\times 120\\\\=2880$

Hence, there are 2880 different words.