If the nth term of 2 ap 975------ and 24,21,18,----are the same find the value of n also find that term
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Given: AP (1) = 9,7,5,......... and AP(2) = 24,21,18,..........
Let a(n) be the nth term of AP(1) and a'(n) be the nth term of AP(2)
Formula for nth term of AP = a+(n-1)d, where a is the first term, n is the number of terms and d is the difference between each term.
thus, calculating a(n) = a+(n-1)d
= 9+(n-1)(-2)
= 9-2n+2
a(n) = 11-2n
Similarly, a'(n)= 24+(n-1)(-3)
= 24-3n+3
a'(n)= 27-3n
Now, as given in the question that the nth term of AP(1) and AP(2) are same
So, a(n)=a'(n)
11-2n=27-3n
n=16
thus value of n is 16
now calculating the value of nth term
put n=16 in either a(n) or a'(n)
a(n) = 11-2(n)
= 11-2(16)
= 11-32
= 21
so the nth term of both the APs is 21
Let a(n) be the nth term of AP(1) and a'(n) be the nth term of AP(2)
Formula for nth term of AP = a+(n-1)d, where a is the first term, n is the number of terms and d is the difference between each term.
thus, calculating a(n) = a+(n-1)d
= 9+(n-1)(-2)
= 9-2n+2
a(n) = 11-2n
Similarly, a'(n)= 24+(n-1)(-3)
= 24-3n+3
a'(n)= 27-3n
Now, as given in the question that the nth term of AP(1) and AP(2) are same
So, a(n)=a'(n)
11-2n=27-3n
n=16
thus value of n is 16
now calculating the value of nth term
put n=16 in either a(n) or a'(n)
a(n) = 11-2(n)
= 11-2(16)
= 11-32
= 21
so the nth term of both the APs is 21
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