Question

If the point (3, 4) lies on the graph of linear equation 3y = ax + 7, find the value of a.

Answer 1

ax=3y+7
x=3y,=4
a=3×4+7/3
a=19/3

Answer 2

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The given equation is → 3y = ax+7

According to the question, x = 3, y = 4

Now,Substituting the values of x and y in the equation 3y = ax+7,we get,

(3×4) = (a×3)

⇒ 12=3a + 7

⇒ 3a + 7 = 12

⇒ 3a = 12 - 7

⇒ 3a = 5

⇒ a = $\frac{5}{3}$

The value of a, if the point (3,4) lies on the graph of the equation 3y=ax+7 is 5/3.