Question

If the radius of a droplet becomes half, then terminal velocity becomes 4Times or ONE FOURTH times?

Answer 1

well yeh is question ka answer nii h WO

2nd question ka answer h

Answer 2

Answer:

The new terminal velocity becomes one fourth times of the original terminal velocity.

Explanation:

We know that,

The formula of terminal velocity is defined as:

$v= \dfrac{2r^2(\rho-\sigma)g}{9\eta}$....(I)

Where, r = radius

g = acceleration due to gravity

All parameters are constant except v and r

Therefore, v is directly proportional to r²

If the radius of a droplet becomes half, then terminal velocity

$v'= \dfrac{2(\dfrac{r}{2})^2(\rho-\sigma)g}{9\eta}$....(II)

Dividing equation(I) by equation (II)

$\dfrac{v}{v'}=4$

$v'=\dfrac{v}{4}$

Hence, The new terminal velocity becomes one fourth times of the original terminal velocity.