Question

If the value of acceleration due to gravity is 10 m/s and the
time of flight is 5 seconds, then the maximum height
reached by the projectile is nearly​

Answer 1

Answer:

31.25 metres

Explanation:

Before finding the maximum height we have to find the initial velocity

so we are using the total time of flight formula

T = 2u/g

5= 2u/10

u= 25 m/s

Now we have to find the maximum height...

h= u^2/2g

h = 25^2/20

h= 625/20

h= 31.25 m