If the zeroes of the polynomial f(x)=x cube-3x square+x+1 are a-b, a, a+b, find the a and b
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sum of zeros=-b/a
3=3a
a=1
product of zeros=-c/a
(a^2 -b^2)a=-1
b=√2
3=3a
a=1
product of zeros=-c/a
(a^2 -b^2)a=-1
b=√2
bhatiavishveshpa8xxn:
But you need to solve it at last.
Product of zeroes is not -c/a. It's c/a
for a cubic eqn it is -c/a
for quadratic it is c/a
Ok
But please solve it at last
Thank you you don't need to solve it last
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