if theta equals to 30 degree find sin 15 degree
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Please see the attached file for your answer
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Answered by
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First of all we know that ,
sinθ=√(1+cos2θ)/2
now
sin15
=√(1-cos30/2)
=√(1-√3/2)/2
=√2-√3/4
=√(2-√3/4)
=(√2-√3)/√4
=[ √(2-√3)] /2
✖ multiplying numerator and denominator by √2
we get
= [ √( 4-√6) ] /2√2
=√(√3-1)²/2√2
=√3-1/2√2
sinθ=√(1+cos2θ)/2
now
sin15
=√(1-cos30/2)
=√(1-√3/2)/2
=√2-√3/4
=√(2-√3/4)
=(√2-√3)/√4
=[ √(2-√3)] /2
✖ multiplying numerator and denominator by √2
we get
= [ √( 4-√6) ] /2√2
=√(√3-1)²/2√2
=√3-1/2√2
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