Question

If Triangle ABC,if a=2, b=3 and sin A=2/3, then​

Answer 1

Answer:

The value of angle B is  $\dfrac{\pi }{4}$

Step-by-step explanation:

Given as :

For any triangle ABC

a = 2  

b = 3

Sin A = $\dfrac{2}{3}$

Let The value of ∠B = x°

According to question

By Applying Sin Law , we get

$\dfrac{a}{SinA}$  = $\dfrac{b}{SinB}$ = $\dfrac{c}{SinC}$

Or,   $\dfrac{a}{SinA}$   =  $\dfrac{b}{SinB}$

Or, $\dfrac{2}{\dfrac{2}{3} }$  =  $\dfrac{3}{SinB}$

Or, $\dfrac{6}{2}$  = $\dfrac{3}{SinB}$

or, $\dfrac{3}{SinB}$ = 3

∴  Sin B = $\dfrac{3}{3}$

i.e Sin B = 1

Or, B = $Sin^{-1}$ 1

So, B = $\dfrac{\pi }{4}$

So, The value of angle B = $\dfrac{\pi }{4}$

Hence , The value of angle B is  $\dfrac{\pi }{4}$   Answer