If triangle ABC similar to triangle DEF then prove that perimeter of abc/ perimeter of def =ab/de=bc/ef=ac/df
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we know that at triangleABC/DEF=(AB/DE)2
we know this by area theorem hence perimeter is √(AB/DE)2
which is AB/DE which is also Whittall to other corresponding sides
we know this by area theorem hence perimeter is √(AB/DE)2
which is AB/DE which is also Whittall to other corresponding sides
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