Question

If x^1/3+y^1/3+z^1/3=0,find x+y+z

Answer 1

X1/3+ Y1/3+Z1/3 = 0
X1/3+ Y1/3 = -Z1/3       Point as 1 equation
Cube on both side
X + y +z= -3(xy)1/3 (x1/3+ y1/3)
Put the eq 1
x+y+z= -3(xy)1/3  (-z)1/3
          =3(xyz)
Answer