Math, asked by sattuy, 1 year ago

If x= 1/7,y=2/3 and z=_1/3 , verify that,x×(y+z)=(x+y)+(xxz)

Answers

Answered by avikamagarwal2006

4

Answer:

x=1/7

y=2/3

z=1/3

To verify

x(y+z)=(x+y)+x×z

1/7(2/3+1/3)=(1/7+2/3)+1/7×1/3

=1/7×3/3=17/21+1/21

=1/7=18/21 ?

=1/7 is not equal to 6/7

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