If x= 1/7,y=2/3 and z=_1/3 , verify that,x×(y+z)=(x+y)+(xxz)
Answers
Answered by
4
Answer:
x=1/7
y=2/3
z=1/3
To verify
x(y+z)=(x+y)+x×z
1/7(2/3+1/3)=(1/7+2/3)+1/7×1/3
=1/7×3/3=17/21+1/21
=1/7=18/21 ?
=1/7 is not equal to 6/7
Similar questions