if x=1+root2+root3,then the value of x+1/x ???
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x=1+√2+√3
=1+1.4+1.7
=4.1
x²=(1+√2+√3)(1+√2+√3)
=1+√2+√3+√2+2+√6+√3+√6+3
=6+2√2+2√3+2√6
=6+2*1.4 +2*1.7+2*2.4
=17
now
x+1/x
=(x²+1)/x
={17+1}/4.1
=18/4.1
=4.39 (approx)
=1+1.4+1.7
=4.1
x²=(1+√2+√3)(1+√2+√3)
=1+√2+√3+√2+2+√6+√3+√6+3
=6+2√2+2√3+2√6
=6+2*1.4 +2*1.7+2*2.4
=17
now
x+1/x
=(x²+1)/x
={17+1}/4.1
=18/4.1
=4.39 (approx)
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fri apka ans finished.Agar itna bara ans hota to koi saf x ki jaga per 1+root2+root3 la kar ans bol data.Ans to ayaga chota
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