if x+1/x=11 find the value of x^2+1/x2
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Answered by
5
Hi Friend !!!
Here is ur answer !!!
x+1/x = 11
(x+1/x)² = 11²
x²+1/x² + 2(x)(1/x) = 121
x²+1/x² +2 = 121
x²+1/x² = 121-2
x²+1/x² = 119
Hope it helps u :-)
Here is ur answer !!!
x+1/x = 11
(x+1/x)² = 11²
x²+1/x² + 2(x)(1/x) = 121
x²+1/x² +2 = 121
x²+1/x² = 121-2
x²+1/x² = 119
Hope it helps u :-)
zahir79:
thnx
Answered by
0
Hey mate...
Your answer is here
SOLUTION ==
Given x - 1/x = 11
squaring on both sides we get
⇒ (x-1/x)2=112
⇒ x2+1/x2-2(x)(1/x)=121......(a-b)2=a2+b2-2ab
⇒ x2+1/x2-2=121
⇒ x2+1/x2 = 121+2 = 123
∴ x2+1/x2=123 answer
☺️
I hope it will help you
#yahyaahmad#
Your answer is here
SOLUTION ==
Given x - 1/x = 11
squaring on both sides we get
⇒ (x-1/x)2=112
⇒ x2+1/x2-2(x)(1/x)=121......(a-b)2=a2+b2-2ab
⇒ x2+1/x2-2=121
⇒ x2+1/x2 = 121+2 = 123
∴ x2+1/x2=123 answer
☺️
I hope it will help you
#yahyaahmad#
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