Question

if x^2 +6x + (k+2) =0 have equal roots , find the value of k​

Answer 1

Answer:

The value of k is 7

Step-by-step explanation:

comparing the quadratic equation x^2+6x+(k+2)=0 with the quadratic equation ax^2+bx+c0

we get, a=1,b=6,c=(k+2)

since the roots are equal

b^2-4ac=0

6^2-4*1(k+2)=0

36-4k-8=0

-4k+28=0

-4k= -28

k=28/4

k= 7

Answer 2

Step-by-step explanation:

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