Question

if x=3,y=2 then (x-y)(x^2+xy+y^2) is

Answer 1

substitute x=3 and y=2
you will get the answer
x^3 - y^3=(x-y)(x^2+xy+y^2)
SO,
x^3-y^3=3^3-2^3
=27 -8
=19
therefore,nineteen is the required answer
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Answer 2

Putting the value of x and y in the given equation.

Step-by-step explanation:

Given:

$x=3\\y=2\\(x-y)(x^2+xy+y^2)$

Computation:

Putting the value of x and y in the given equation.

$(x-y)(x^2+xy+y^2)$

$(3-2)[3^2+(3)(2)+2^2]$

$(1)[9+6+4]$

$(1)[19]$

$19$

Therefore, 19 is the solution to the given question.

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